Question:

The correct order of increasing C–O bond length in CO, CO\(_3^{2-}\), CO\(_2\) is:

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Higher bond order means shorter bond length.
Updated On: Mar 24, 2026
  • CO < CO\(_2\) < CO\(_3^{2-}\)
  • CO\(_2\) < CO\(_3^{2-}\) < CO
  • CO < CO\(_3^{2-}\) < CO\(_2\)
  • CO\(_3^{2-}\) < CO\(_2\) < CO
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The Correct Option is A

Solution and Explanation


Step 1:
Bond order inversely proportional to bond length.
Step 2:
\[ \text{CO (bond order 3)} < \text{CO}_2 \text{ (bond order 2)} < \text{CO}_3^{2-} \text{ (bond order }1\frac{1}{3}) \]
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