Question:
For the dissociation reaction, \( \text{H}_2 \rightarrow \text{H} + \text{H} \), \( \Delta H = 162 \, \text{Kcal} \), heat of atomisation of H is
For the dissociation reaction, \( \text{H}_2 \rightarrow \text{H} + \text{H} \), \( \Delta H = 162 \, \text{Kcal} \), heat of atomisation of H is
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The heat of atomisation is half the heat of dissociation for diatomic molecules like \( \text{H}_2 \).
Updated On: Mar 24, 2026
- 81 Kcal
- 162 Kcal
- 162 Kcal
- 218 Kcal
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The Correct Option is A
Solution and Explanation
Step 1: Apply the concept of enthalpy change.
In the dissociation of \( \text{H}_2 \), the heat of atomisation is half of the given value of \( \Delta H \).
Step 2: Conclusion.
The heat of atomisation of H is \( 81 \, \text{Kcal} \). Final Answer: \[ \boxed{81 \, \text{Kcal}} \]
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