Question:
Bond enthalpies of \( H_2 \), \( X_2 \), and \( HX \) are in the ratio 2:1:2. If enthalpy of formation of \( HX \) is -50 kJ/mol\(^{-1}\), the bond enthalpy of \( X_2 \) is:
Bond enthalpies of \( H_2 \), \( X_2 \), and \( HX \) are in the ratio 2:1:2. If enthalpy of formation of \( HX \) is -50 kJ/mol\(^{-1}\), the bond enthalpy of \( X_2 \) is:
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Bond enthalpies can be used to calculate enthalpy changes based on the ratio of bond strengths in the molecules involved.
Updated On: Mar 25, 2026
- 100 kJ/mol\(^{-1}\)
- 300 kJ/mol\(^{-1}\)
- 200 kJ/mol\(^{-1}\)
- 400 kJ/mol\(^{-1}\)
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The Correct Option is A
Solution and Explanation
Step 1: Bond enthalpy relationship.
Using the given bond enthalpies and enthalpy of formation, we can set up the following relation: \[ \text{Bond enthalpy of } X_2 = 100 \, \text{kJ/mol} \] This is calculated based on the given ratio and the bond enthalpy formula.
Thus, the correct answer is (1).
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