Question

The correct order of increasing acidic behavior of the following compounds is:

• A. $A > B > C$
• B. $C > B > A$
• C. $A > C > B$
• D. $B > C > A$

Hint:

More bonds between carbons = More s-character = More acidic.

Answer 1

The Correct Option is B

Step 1: Concept
The acidity of hydrocarbons depends on the hybridization of the carbon atom.

Step 2: Meaning
Higher “s-character” in the hybrid orbital makes the carbon more electronegative, allowing it to better stabilize the negative charge after losing a proton ($H^+$).

Step 3: Analysis
Ethyne (C) is $sp$ hybridized (50% s), Ethene (B) is $sp^2$ (33% s), and Ethane (A) is $sp^3$ (25% s). Higher electronegativity leads to higher acidity.

Step 4: Conclusion
Thus, the order of acidity is Ethyne $>$ Ethene $>$ Ethane ($C > B > A$). Final Answer: (B)