Question

The capacity of a capacitor is \( 4 \times 10^{-6} \, \text{F} \) and its potential is 100 V. The charge on the plates is:

• A. \( 4 \times 10^{-4} \, \text{C} \)
• B. \( 5 \times 10^{-6} \, \text{C} \)
• C. \( 10^{-6} \, \text{C} \)
• D. \( 3 \times 10^{-6} \, \text{C} \)

Hint:

The charge on a capacitor is the product of its capacitance and potential difference.

Answer 1

The Correct Option is A

Step 1: Use the formula for capacitance.
The charge on the capacitor is given by the formula: \[ Q = C \times V \] where \( C \) is the capacitance and \( V \) is the potential difference.
Step 2: Calculate the charge.
Substituting the given values: \[ Q = 4 \times 10^{-6} \, \text{F} \times 100 \, \text{V} = 4 \times 10^{-4} \, \text{C} \]
Final Answer: \[ \boxed{4 \times 10^{-4} \, \text{C}} \]