If the force exerted by an electric dipole on a charge \(q\) at a distance of 1 m is \(F\), the force at a point 2 m away in the same direction will be
Show Hint
For a dipole, field and force vary as \(1/r^3\), so doubling distance reduces force by \(8\) times.
Step 1: Recall electric field due to dipole on axial line.
Electric field due to dipole at distance \(r\) on axial line is:
\[
E \propto \frac{1}{r^3}
\] Step 2: Force on charge \(q\).
\[
F = qE
\Rightarrow F \propto \frac{1}{r^3}
\] Step 3: Compare force at \(r=1m\) and \(r=2m\).
\[
\frac{F_2}{F_1} = \left(\frac{1}{2}\right)^3 = \frac{1}{8}
\] Step 4: Write final relation.
\[
F_2 = \frac{F_1}{8} = \frac{F}{8}
\] Final Answer:
\[
\boxed{\frac{F}{8}}
\]