Question

A parallel plate capacitor with plate area \(A\) and separation \(d\) is filled with a dielectric of constant \(K\). The capacitance becomes:

• A. \(\varepsilon_0A/d\)
• B. \(K\varepsilon_0A/d\)
• C. \(\varepsilon_0A/Kd\)
• D. \(K^2\varepsilon_0A/d\)

Hint:

Dielectric increases capacitance by factor \(K\).

Answer 1

The Correct Option is B

Insertion of dielectric multiplies capacitance by \(K\): \[ C=K\varepsilon_0\frac{A}{d} \]