The best method for the conversion of an alcohol into an alkyl chloride is by treating the alcohol with
Show Hint
- $PCl_{3}$
- $PCl_{5}$
- $SOCl_{2}$ in presence of pyridine
- dry HCl in the presence of anhydrous $ZnCl_{2}$
The Correct Option is C
Solution and Explanation
$ROH + SOCl_2 \xrightarrow{\text{pyridine}} RCl + SO_2(g) + HCl(g)$.
Step 2: Analysis of Byproducts
The byproducts $SO_2$ and $HCl$ are both gases.
Step 3: Conclusion
Because the byproducts easily escape, it leaves behind pure alkyl chloride without the need for complex separation, making it the "best" method.
Final Answer: (c)
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