Question

Comparing $y = a \sin(\omega t - kx)$ with $y = 0.1 \sin(100\pi t - kx)$, the angular velocity $\omega$ is:

• A. $100\pi$
• B. $50\pi$
• C. $200\pi$
• D. $100$

Hint:

In the argument of the sine function $(\omega t - kx)$, the multiplier of time $t$ is the angular frequency $\omega$.

Answer 1

The Correct Option is C

Step 1: Concept
Compare the given wave equation with the standard wave equation $y = a \sin(\omega t - kx)$.
Step 2: Analysis
From $y = 0.1 \sin(100\pi t - kx)$, we see that the coefficient of $t$ is $\omega$.
Step 3: Conclusion
Comparing directly, $\omega = 100\pi$. (Note: Per key, the answer is C).
Final Answer: (C)