Question:
The angle of minimum deviation \( \delta_m \) for an equilateral glass prism is \( 30^\circ \). The refractive index of the prism is
The angle of minimum deviation \( \delta_m \) for an equilateral glass prism is \( 30^\circ \). The refractive index of the prism is
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The angle of minimum deviation $\deltam$ for an equilateral glass prism is $30
Updated On: Apr 15, 2026
- $1/\sqrt{2}$
- $\sqrt{2}$
- $2\sqrt{2}$
- $1/2\sqrt{2}$
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The Correct Option is B
Solution and Explanation
Step 1: Formula
Refractive index $\mu = \frac{\sin\left(\frac{A+\delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$.
Step 2: Values
Equilateral prism means $A = 60^{\circ}$ and $\delta_m = 30^{\circ}$.
Step 3: Calculation
$$\mu = \frac{\sin(45^{\circ})}{\sin(30^{\circ})} = \frac{1/\sqrt{2}}{1/2} = \sqrt{2}$$
Final Answer: (B)
Refractive index $\mu = \frac{\sin\left(\frac{A+\delta_m}{2}\right)}{\sin\left(\frac{A}{2}\right)}$.
Step 2: Values
Equilateral prism means $A = 60^{\circ}$ and $\delta_m = 30^{\circ}$.
Step 3: Calculation
$$\mu = \frac{\sin(45^{\circ})}{\sin(30^{\circ})} = \frac{1/\sqrt{2}}{1/2} = \sqrt{2}$$
Final Answer: (B)
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