Question:
A beam of light is incident at $60^\circ$ to a plane surface. The reflected and refracted rays are perpendicular to each other then refractive index of the surface is
A beam of light is incident at $60^\circ$ to a plane surface. The reflected and refracted rays are perpendicular to each other then refractive index of the surface is
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A beam of light is incident at $60
Updated On: Apr 15, 2026
- $\sqrt{3}$
- $\frac{1}{\sqrt{3}}$
- $\frac{1}{2\sqrt{3}}$
- None of these
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The Correct Option is A
Solution and Explanation
Step 1: Concept
When reflected and refracted rays are perpendicular, the angle of incidence is the Brewster's angle ($i_p$).
Step 2: Formula
According to Brewster's Law, $\mu = \tan i_{p}$.
Step 3: Calculation
$\mu = \tan 60^{\circ} = \sqrt{3}$.
Final Answer: (A)
When reflected and refracted rays are perpendicular, the angle of incidence is the Brewster's angle ($i_p$).
Step 2: Formula
According to Brewster's Law, $\mu = \tan i_{p}$.
Step 3: Calculation
$\mu = \tan 60^{\circ} = \sqrt{3}$.
Final Answer: (A)
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