Question:

The angle between the lines whose intercepts on the axes are (a,-b) and (b,-a) respectively, is

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Use tanθ=|(m₁-m₂)/(1+m₁m₂)|.
Updated On: Mar 19, 2026
  • tan⁻1((a²-b²)/(ab))
  • tan⁻1((b²-a²)/(2))
  • tan⁻1((b²-a²)/(2ab))
  • None of these
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The Correct Option is C

Solution and Explanation

Slopes: m₁=-(b)/(a), m₂=-(a)/(b) tanθ=|(m₁-m₂)/(1+m₁m₂)| =|((a²-b²)/(ab))/(2)| =(|b²-a²|)/(2ab)
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