Question:
The amplitude of the sinusoidially oscillating electric field of a plane wave is $ 60\, V/m $ . Then the amplitude of magnetic field is:
The amplitude of the sinusoidially oscillating electric field of a plane wave is $ 60\, V/m $ . Then the amplitude of magnetic field is:
Updated On: Jun 6, 2022
- $ 2\times {{10}^{2}}T $
- $ 6\times {{10}^{7}}T $
- $ 6\times {{10}^{2}}T $
- $ 2\times {{10}^{-7}}T $
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The Correct Option is D
Solution and Explanation
The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as
$ \frac{E}{B}=c $ $ \Rightarrow $ $ B=\frac{E}{c} $
Given, $ E=60\,V/m,c=3\times {{10}^{8}}m/s $
$ \therefore $ $ B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T $
$ \frac{E}{B}=c $ $ \Rightarrow $ $ B=\frac{E}{c} $
Given, $ E=60\,V/m,c=3\times {{10}^{8}}m/s $
$ \therefore $ $ B=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T $
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Concepts Used:
Displacement Current
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