Step 1: Use the formula relating power and torque.
The power \( P \) in rotational motion is related to torque \( \tau \) and angular velocity \( \omega \) by the formula:
\[
P = \tau \cdot \omega
\]
Step 2: Rearrange the equation to solve for angular velocity.
Rearrange the equation to solve for \( \omega \):
\[
\omega = \frac{P}{\tau}
\]
Step 3: Substitute the known values.
Substitute \( P = 150 \, \text{kW} = 150 \times 10^3 \, \text{W} \) and \( \tau = 100 \, \text{Nm} \):
\[
\omega = \frac{150 \times 10^3}{100} = 1500 \, \text{rad/s}
\]
Thus, the angular velocity is:
\[
\boxed{1500 \, \text{rad/s}}
\]