The anti derivative of sin 2x is a function of x whose derivative is sin 2x. It is known that,
\(\frac{d}{dx}\)(cos 2x)=-2sin 2x
\(\Rightarrow\) sin 2x = -\(\frac{1}{2}\frac{d}{dx}\)(cos2x)
∴ sin 2x = \(\frac{d}{dx}\bigg(-\frac{1}{2}cos2x\bigg)\)
Therefore, the anti derivative of sin 2x is -\(\frac{1}{2}\) cos 2x
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
Find the area of the region bounded by the curve y2=x and the lines x=1,x=4 and the x-axis
Find the area of the region bounded by y2=9x, x=2, x=4 and the x-axis in the first quadrant.
Find the area of the region bounded by x2=4y,y=2,y=4 and the x-axis in the first quadrant.
Find the area of the region bounded by the ellipse \(\frac{x^2}{16}+\frac{y^2}{9}=1\)
The representation of the area of a region under a curve is called to be as integral. The actual value of an integral can be acquired (approximately) by drawing rectangles.
Also, F(x) is known to be a Newton-Leibnitz integral or antiderivative or primitive of a function f(x) on an interval I.
F'(x) = f(x)
For every value of x = I.
Integral calculus helps to resolve two major types of problems: