Question

SiCl\(_4\) on hydrolysis forms \(X\) and HCl. Compound \(X\) loses water at \(1000^\circ C\) and gives \(Y\). Compounds \(X\) and \(Y\) respectively are

• A. \(H_2SiCl_6,\;SiO_2\)
• B. \(H_2SiO_3,\;SiO_2\)
• C. \(SiO_2,\;SiO_2\)
• D. \(H_4SiO_4,\;SiO_2\)

Hint:

Hydrolysis of \(SiCl_4\) gives orthosilicic acid \(H_4SiO_4\), which on strong heating dehydrates to \(SiO_2\).

Answer 1

The Correct Option is D

Step 1: Hydrolysis of \(SiCl_4\).
\[ SiCl_4 + 4H_2O \rightarrow H_4SiO_4 + 4HCl \]
So:
\[ X = H_4SiO_4 \]
Step 2: Dehydration at high temperature.
At \(1000^\circ C\), silicic acid loses water to form silica:
\[ H_4SiO_4 \rightarrow SiO_2 + 2H_2O \]
So:
\[ Y = SiO_2 \]
Final Answer:
\[ \boxed{H_4SiO_4,\;SiO_2} \]