The equation \( \mathbf{E} = \rho \mathbf{J} \) is known as the electrical conductivity equation. Here:
From this equation, we can express the electric field in terms of current density:
\[ \mathbf{E} = \rho \mathbf{J} \]
Now, consider **Ohm's law**, which states that the current density \( \mathbf{J} \) is proportional to the electric field \( \mathbf{E} \) and the material's conductivity \( \sigma \) (the inverse of resistivity). So, we can write:
\[ \mathbf{J} = \sigma \mathbf{E} \]
Since \( \sigma = \frac{1}{\rho} \), we can substitute this into the above equation:
\[ \mathbf{J} = \frac{1}{\rho} \mathbf{E} \]
Rearranging the equation, we get:
\[ \mathbf{E} = \rho \mathbf{J} \]
This is exactly the form of the equation we started with, so we have derived Ohm's law from the equation \( \mathbf{E} = \rho \mathbf{J} \).
Ohm's law assumes that the material has a constant resistivity \( \rho \) and that the current is proportional to the applied voltage (i.e., linear response). However, there are conditions under which Ohm's law does not hold:
Thus, Ohm’s law is not valid in situations where the material’s resistivity is not constant or when extreme conditions like high electric fields or temperatures cause a non-linear relationship between voltage and current.
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

A racing track is built around an elliptical ground whose equation is given by \[ 9x^2 + 16y^2 = 144 \] The width of the track is \(3\) m as shown. Based on the given information answer the following: 
(i) Express \(y\) as a function of \(x\) from the given equation of ellipse.
(ii) Integrate the function obtained in (i) with respect to \(x\).
(iii)(a) Find the area of the region enclosed within the elliptical ground excluding the track using integration.
OR
(iii)(b) Write the coordinates of the points \(P\) and \(Q\) where the outer edge of the track cuts \(x\)-axis and \(y\)-axis in first quadrant and find the area of triangle formed by points \(P,O,Q\).