Show that
(i)\(\begin{bmatrix}5&-1\\6&7\end{bmatrix}\)\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)\(\neq \begin{bmatrix}2&1\\3&4\end{bmatrix}\begin{bmatrix}5&-1\\6&7\end{bmatrix}\)
(ii)\(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)\(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)\(\neq \) \(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)\(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)
(i)\(\begin{bmatrix}5&-1\\6&7\end{bmatrix}\)\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)
=\(\begin{bmatrix}5(2)-1(3)&5(1)-1(4)\\6(2)+7(3)&6(1)+7(4)\end{bmatrix}\)
=\(\begin{bmatrix}10-3&5-4\\12+21&6+28\end{bmatrix}\)=\(\begin{bmatrix}7&1\\33&34\end{bmatrix}\)
\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)
=\(\begin{bmatrix}2(5)+1(6)&2(-1)+1(7)\\3(5)+4(6)&3(-1)+4(7)\end{bmatrix}\)
=\(\begin{bmatrix}10+6&-2+7\\15+24&-3+28\end{bmatrix}\)
=[\(\begin{bmatrix}16&5\\39&25\end{bmatrix}\)
\(\therefore\) \(\begin{bmatrix}5&-1\\6&7\end{bmatrix}\)\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)≠\(\begin{bmatrix}2&1\\3&4\end{bmatrix}\)\(\begin{bmatrix}5&-1\\6&7\end{bmatrix}\)
(ii)\(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)\(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)
=\(\begin{bmatrix}1(-1)+2(0)+3(2)&1(1)+2(-1)+3(3)&1(0)+2(-1)+3(4)\\0(-1)+1(0)+0(2)&0(1)+1(-1)+0(3)&0(0)+1(1)+0(4)\\1(-1)+1(0)+0(2)&1(1)+1(-1)+0(3)&1(0)+1(1)+0(4)\end{bmatrix}\)
=\(\begin{bmatrix}5&8&14\\0&-1&1\\ -1&0&1\end{bmatrix}\)
\(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)\(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)
=\(\begin{bmatrix}-1(1)1(0)+0(1)&-1(2)+1(1)+0(1)&-1(3)+1(0)+0(0)\\0(1)+(-1(0)+1(1)&0(2)+(-1)(1)+1(1)&0(3)+(-1)(0)+1(0)\\2(1)+3(0)+4(1)&2(2)+3(1)+4(1)&2(3)+3(0)+4(0)\end{bmatrix}\)
=\(\begin{bmatrix}-1&-1&-3\\1&0&0\\ 6&11&6\end{bmatrix}\)
\(\therefore\) \(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)\(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)≠ \(\begin{bmatrix}-1&1&0\\0&-1&1\\ 2&3&4\end{bmatrix}\)\(\begin{bmatrix}1&2&3\\0&1&0\\ 1&1&0\end{bmatrix}\)
Determine whether each of the following relations are reflexive, symmetric, and transitive.
Show that the relation R in the set R of real numbers, defined as
R = {(a, b): a ≤ b2 } is neither reflexive nor symmetric nor transitive.
Check whether the relation R defined in the set {1, 2, 3, 4, 5, 6} as
R = {(a, b): b = a + 1} is reflexive, symmetric or transitive.
In the matrix A= \(\begin{bmatrix} 2 & 5 & 19&-7 \\ 35 & -2 & \frac{5}{2}&12 \\ \sqrt3 & 1 & -5&17 \end{bmatrix}\),write:
I. The order of the matrix
II. The number of elements
III. Write the elements a13, a21, a33, a24, a23
If a matrix has 24 elements, what are the possible order it can have? What, if it has 13 elements?
If a matrix has 18 elements, what are the possible orders it can have? What, if it has 5 elements?
Construct a 3×4 matrix, whose elements are given by
I. \(a_{ij}=\frac{1}{2}\mid -3i+j\mid\)
II. \(a_{ij}=2i-j\)
Find the value of x, y, and z from the following equation:
I.\(\begin{bmatrix} 4&3&\\x&5\end{bmatrix}=\begin{bmatrix}y&z\\1&5\end{bmatrix}\)
II. \(\begin{bmatrix}x+y&2\\5+z&xy\end{bmatrix}=\begin{bmatrix}6&2\\5&8\end{bmatrix}\)
III. \(\begin{bmatrix}x+y+z\\x+z\\y+z\end{bmatrix}=\begin{bmatrix}9\\5\\7\end{bmatrix}\)