Question:

Select the correct option :

Show Hint

Species richness is highest in the tropics. Columbia has about 1400 bird species and New York about 105.
Updated On: Oct 22, 2026
  • Tropics between \( 23.5^{\circ}\ \mathrm{N} - 23.5^{\circ}\ \mathrm{S} \) - Higher biodiversity than temperate areas
  • Columbia - 105 bird species
  • New York - 1400 bird species
  • India - 2000 bird species
Show Solution
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The Correct Option is A

Solution and Explanation

Step 1: Recall the pattern:
Biodiversity is not spread evenly. It is highest near the equator and falls toward the poles. This is the latitudinal gradient.

Step 2: Check option (A):
The tropics lie between \( 23.5^{\circ} \) N and \( 23.5^{\circ} \) S. They have more species than temperate areas.
Reasons are stable climate, more solar energy and more productivity. So (A) is TRUE.

Step 3: Check option (B):
Columbia has about 1400 bird species, not 105. So (B) is FALSE.

Step 4: Check option (C):
New York at 41 degrees N has about 105 bird species, not 1400. The numbers of (B) and (C) are swapped. So (C) is FALSE.

Step 5: Check option (D):
India has about 1200 bird species, not 2000. So (D) is FALSE.

Final Answer:
Only the statement about the tropics is correct. This is option (A). \[ \boxed{\text{(A)}} \]
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