Proton \((\mathrm{P})\) and electron \((\mathrm{e})\) will have same de-Broglie wavelength when the ratio of their momentum is (assume, \(m_p=1849\,m_e\)):
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- 1 : 1
- 1 : 43
- 1 : 1849
- 43 : 1
The Correct Option is A
Solution and Explanation
For the proton and the electron to have the same wavelength, \(\dfrac{h}{p_p}=\dfrac{h}{p_e}\Rightarrow p_p=p_e\).
Hence \(p_p:p_e=1:1\). The given mass ratio \(m_p=1849\,m_e\) is not needed.
Answer: (1) 1 : 1
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