The correct option is (B): \(\frac{1}{8}\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,

The de Broglie wavelengths of a proton and an α particle are \( \lambda \) and \( 2\lambda \) respectively. The ratio of the velocities of proton and α particle will be:
The de-Broglie wavelength of an electron is the same as that of a photon. If the velocity of the electron is 25% of the velocity of light, then the ratio of the K.E. of the electron to the K.E. of the photon will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
As per De-Morgan's first theorem, the complement outcomes of the AND operation are equivalent to the OR operation of the complement of that variable. Thus, it is equivalent to the NAND function and is a negative-OR function manifest that (A.B)' = A'+B' and we can show this using the given table.

As per De-Morgan's second theorem, the complement outcomes of the OR operation are equivalent o the AND operation of the complement of that variable. Thus, it is the equal of the NOR function and is a negative-AND function that manifests that (A+B)' = A'.B' and we can represent this using the given truth table.
