Question:

A source of monochromatic light liberates 9 \( \times \) 1020 photon per second with wavelength 600 nm when operated at 400 W. The number of photons emitted per second with wavelength of 800 nm by the source of monochromatic light operating at same power will be :

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Power = (number of photons per second) × (energy per photon = hc/\(\lambda\)); for fixed power, the photon rate is proportional to the wavelength.
Updated On: Oct 31, 2026
  • 12 \( \times \) 1020
  • 6 \( \times \) 1020
  • 9 \( \times \) 1020
  • 24 \( \times \) 1020
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The Correct Option is A

Solution and Explanation

Step 1: Power P = n × hc/\(\lambda\), so n = P\(\lambda\)/(hc).
Step 2: For the same power, n2/n1 = \(\lambda\)2/\(\lambda\)1 = 800/600 = 4/3.
Step 3: n2 = 9 × 1020 × 4/3 = 12 × 1020 photons per second.
Answer: (A) 12 × 1020
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