Question:
Photographic paper is developed with alkaline hydroquinone. Select correct statement.
Photographic paper is developed with alkaline hydroquinone. Select correct statement.
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Oxidant = gets reduced (gains electrons). Reductant = gets oxidised (loses electrons).
Updated On: Apr 23, 2026
- Hydroquinone is the oxidant
- Ag\(^+\) is the oxidant
- Br\(^-\) is the oxidant
- Ag\(^+\) is the reductant
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
In photographic development, exposed AgBr is reduced to Ag metal. Hydroquinone is the reducing agent.
Step 2: Detailed Explanation:
Ag\(^+\) (in AgBr) + e\(^-\) \(\rightarrow\) Ag(s) (reduction). Ag\(^+\) accepts electrons \(\Rightarrow\) oxidant.
Hydroquinone is oxidised to quinone, donates electrons \(\Rightarrow\) reductant.
Step 3: Final Answer:
Thus, Ag\(^+\) is the oxidant.
In photographic development, exposed AgBr is reduced to Ag metal. Hydroquinone is the reducing agent.
Step 2: Detailed Explanation:
Ag\(^+\) (in AgBr) + e\(^-\) \(\rightarrow\) Ag(s) (reduction). Ag\(^+\) accepts electrons \(\Rightarrow\) oxidant.
Hydroquinone is oxidised to quinone, donates electrons \(\Rightarrow\) reductant.
Step 3: Final Answer:
Thus, Ag\(^+\) is the oxidant.
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