Question:

Phenol reacts with bromine ($Br_{2}$) to give ______ presence of $CS_{2}$ in low temperature:

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$CS_{2}$ (Non-polar) = Mono-substitution (Para); $H_{2}O$ (Polar) = Tri-substitution (2,4,6).
Updated On: May 15, 2026
  • m-Bromophenol
  • p-Bromophenol
  • o,p-Dibromophenol
  • 2,4,6-tribromophenol
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The Correct Option is B

Solution and Explanation


Step 1: Concept

Bromination of phenol is an electrophilic aromatic substitution reaction.

Step 2: Meaning

The solvent and temperature significantly influence the extent of substitution.

Step 3: Analysis

In non-polar solvents like $CS_{2}$ at low temperature, the monobromination occurs, yielding mainly p-bromophenol (and some ortho). In aqueous medium ($Br_{2}$ water), 2,4,6-tribromophenol is formed.

Step 4: Conclusion

In the presence of $CS_{2}$ at low temperature, p-bromophenol is the major product. Final Answer: (B)
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