Question:
Optically active mandelic acid can be synthesized from benzaldehyde in the presence of the enzyme:
Optically active mandelic acid can be synthesized from benzaldehyde in the presence of the enzyme:
Updated On: Mar 5, 2026
- Invertin
- Myrosin
- Emulsin
- Zymase
Show Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Mandelic acid is an alpha-hydroxy acid derived from natural sources such as almonds. The synthesis of optically active mandelic acid from benzaldehyde can be facilitated by certain enzymes. In this context, we need to identify which enzyme from the given options can perform this conversion.
- Understanding the Role of Enzymes: Enzymes are biological catalysts that accelerate chemical reactions. For producing optically active compounds, specific enzymes can catalyze asymmetric synthesis, which is responsible for producing chiral centers.
- Options Analysis:
- Invertin: This enzyme is typically associated with the conversion of sucrose into glucose and fructose, and it is not involved in the synthesis of mandelic acid.
- Myrosin: Myrosinase is involved in the hydrolysis of glucosinolates but is not relevant to the synthesis of mandelic acid from benzaldehyde.
- Emulsin: This is an enzyme preparation used to catalyze certain glycoside reactions. Emulsin is known for hydrolyzing certain glucosides and has been used in enzymatic reactions involving benzaldehyde.
- Zymase: Zymase is a complex of enzymes that procures fermentation in sugars, primarily used in carbohydrate metabolism.
- Correct Answer Justification: Among the options, Emulsin is the enzyme that can be used to synthesize optically active mandelic acid from benzaldehyde. This is due to its ability to perform specific conversions involving benzaldehyde.
Conclusion: The correct answer is Emulsin as it effectively catalyzes the conversion needed to synthesize mandelic acid.
Was this answer helpful?
0
0
Top GPAT Organic Chemistry Questions
- Given below are the two statements
Statement I: Glucose‐6‐phosphate can be formed from glucose, but not from glycogen.
Statement II: Glucose‐1‐phosphate may be hydrolyzed to yield free glucose in liver.
Choose the most appropriate answer from the options given below: - In the determination of configuration of glucose, Fischer subjected (‐) arabinose to Ruff’s degradation. The four‐carbon sugar obtained by the degradation process was:
- Insertion of a oxygen in a carbonyl compound to form an ester is known as:
- Controlled alkylation of a ketone via an enamine intermediate is named as:
- Among the following organic compounds, the one that is non‐aromatic is:
View More Questions
Top GPAT Amino Acids Questions
- Amine group protection during peptide synthesis can be accomplished by converting the amine to
- All the following can determine the protein structure except
- This Compound 2,5,8,11,14,17,20,23,26-nona-oxaoctacosan-28-yl p-(butylamino) benzoate is usually known for its activity?
- Gabriel ring closure method is employed for the synthesis of :
- Which among the following is a non-essential amino acid?
View More Questions
Top GPAT Questions
- Match the symbols in the List I with the terms used in the List II of conductance measurements, and
List I
SymbolsList II
TermsA \(\Omega^{-1}\) I Specific conductance B \(∧\) II Electrical conductance C k III Specific resistance D \(\rho\) IV Equivalent conductance
Choose the correct answer from the options given below: - Cottrell’s method is used for the measurement of:
- Match the statements in List I with their correct answers in List II, respectively, in respect to modified 1st law of thermodynamics, and
List I
List II
A Constant heat (q = 0) I Isothermal B Reversible process at constant temperature (dT = 0) II Isometric C Constant volume (dV = 0) III Adiabatic D Constant pressure (dP = 0) IV Isobar
Choose the correct answer from the options given below: - Boric acid with molecular weight 61.83 was partitioned between water and amyl alcohol at 25 °C. The amount of boric acid was determined to be 0.24 g in 250 ml of amyl alcohol and 0.32 g in 100 ml water. The partition coefficient of boric acid between water and amyl alcohol, when calculated at molar concentration for each of the solution, is:
- Drugs ‘A’, ‘B’ and ‘C’ follow zero order, first order and second order degradation kinetics, respectively, but have the same rate constant. Which of the following statement is true in this respect:
View More Questions