If A =\(\sum_{n=1}^{\infty}\)\(\frac{1}{( 3 + (-1)^n)^n}\) and B = \(\sum_{n=1}^{\infty}\) \(\frac{(-1)^n}{( 3 + (-1)^n)^n}\) , then A/B is equal to :
Let S be the sample space of all five digit numbers. It p is the probability that a randomly selected number from S, is multiple of 7 but not divisible by 5, then 9p is equal to
Let\(f(x)=\frac{x−1}{x+1},x∈R− \left\{0,−1,1\right\}\)If ƒn+1(x) = ƒ(ƒn(x)) for all n∈N, then ƒ6(6) + ƒ7(7) is equal to :