Let
\(f(x)=\frac{x−1}{x+1},x∈R− \left\{0,−1,1\right\}\)
If ƒn+1(x) = ƒ(ƒn(x)) for all n∈N, then ƒ6(6) + ƒ7(7) is equal to :
\(\frac{7}{6}\)
\(-\frac{3}{2}\)
\(\frac{7}{12}\)
\(-\frac{11}{12}\)
The correct answer is (B) : \(-\frac{3}{2}\)
\(f(x) = \frac{x - 1}{x + 1} \Rightarrow f(f(x)) = \frac{\left(\frac{x - 1}{x + 1}\right) - 1}{\left(\frac{x - 1}{x + 1}\right) + 1} = -\frac{1}{x}\)
\( \Rightarrow f^3(x) = -\frac{x + 1}{x - 1} \Rightarrow f^4(x) = -\frac{\left(\frac{x - 1}{x + 1} + 1\right)}{\left(\frac{x - 1}{x + 1} - 1\right)} = x\)
So, ƒ6(6) + ƒ7(7) = ƒ2(6) + ƒ3(7)
\(= -\frac{1}{6}-\frac{7+1}{7-1}= - \frac{9}{6}=-\frac{3}{2}\)
| List - I | List - II | ||
| (P) | If a = 0, b = 1, c = 0 and d = 0, then | (1) | h is one-one. |
| (Q) | If a = 1, b = 0, c = 0 and d = 0, then | (2) | h is onto. |
| (R) | If a = 0, b = 0, c = 1 and d = 0, then | (3) | h is differentiable on \(\R\) |
| (S) | If a = 0, b = 0, c = 0 and d = 1, then | (4) | the range of h is [0, 1]. |
| (5) | the range of h is {0, 1}. | ||
Let \( f(x) = \sqrt{4 - x^2} \), \( g(x) = \sqrt{x^2 - 1} \). Then the domain of the function \( h(x) = f(x) + g(x) \) is equal to:
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
The composite function refers to the resultant value of two specified functions. When the output derived from the application of a function with a second independent variable function becomes the input of the third function, then it is called a composite function. Also, whose scope includes the values of the independent variable for which the result of the first function is placed in the domain of the second.
In Mathematics, the composition of a function is a process, where two functions say f and g create a new function say h in such a way that h (x) = g (f (x)). Here, we can see function g applies to the function of x i.e., f (x)
Let f: A → B and g: B → C are two functions.
So, the composition of f and g, denoted by gof, is known as the function:
g of: A → C given by gof (x) = g (f (x)), A x ∈ A.