Question:
Neha appeared for her judiciary preliminary examination on 12th November 2009, which was a Thursday. On which of the following dates did 12th November again fall on a Thursday?
Neha appeared for her judiciary preliminary examination on 12th November 2009, which was a Thursday. On which of the following dates did 12th November again fall on a Thursday?
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The day of the week repeats when the sum of odd days becomes a multiple of 7. For non-leap years, the calendar usually repeats after 6 or 11 years.
Updated On: Jun 30, 2026
- 12th November 2014
- 12th November 2015
- 12th November 2016
- 12th November 2017
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The Correct Option is B
Solution and Explanation
Concept:
To find when a specific date falls on the same day of the week, we calculate the number of "Odd Days" between the years.
• Ordinary Year: 365 days = 52 weeks + 1 Odd Day.
• Leap Year: 366 days = 52 weeks + 2 Odd Days.
Step 1: Calculating odd days year by year from 2009.
Nov 2009 to Nov 2010 = 1 (Ordinary) Nov 2010 to Nov 2011 = 1 (Ordinary) Nov 2011 to Nov 2012 = 2 (Leap Year 2012 included) Nov 2012 to Nov 2013 = 1 (Ordinary)
Step 2: Finding the total sum of 7 odd days.
Nov 2013 to Nov 2014 = 1 (Ordinary) Nov 2014 to Nov 2015 = 1 (Ordinary) Total Odd Days = 1 + 1 + 2 + 1 + 1 + 1 =
7. Since 7 odd days = 0 net change in the day of the week, the date will again be a Thursday in
2015.
• Ordinary Year: 365 days = 52 weeks + 1 Odd Day.
• Leap Year: 366 days = 52 weeks + 2 Odd Days.
Step 1: Calculating odd days year by year from 2009.
Nov 2009 to Nov 2010 = 1 (Ordinary) Nov 2010 to Nov 2011 = 1 (Ordinary) Nov 2011 to Nov 2012 = 2 (Leap Year 2012 included) Nov 2012 to Nov 2013 = 1 (Ordinary)
Step 2: Finding the total sum of 7 odd days.
Nov 2013 to Nov 2014 = 1 (Ordinary) Nov 2014 to Nov 2015 = 1 (Ordinary) Total Odd Days = 1 + 1 + 2 + 1 + 1 + 1 =
7. Since 7 odd days = 0 net change in the day of the week, the date will again be a Thursday in
2015.
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