Question

Match the Xenon compounds in Column-1 with its structure in Column-II.

Column – I	Column – II
(a) \(\text{XeF}_4\)	(i) pyramidal
(b) \(\text{XeF}_6\)	(ii) square planar
(c) \(\text{XeOF}_4\)	(iii) distorted octahedral
(d) \(\text{XeO}_3\)	(iv) square pyramidal

• (a) - (ii), (b) - (iii), (c) - (i), (d) - (iv)
• (a) - (iii), (b) - (iv), (c) - (i), (d) - (ii)
• (a) - (i), (b) - (ii), (c) - (iii), (d) - (iv)
• (a) - (ii), (b) - (iii), (c) - (iv), (d) - (i)

Hint:

Use VSEPR: XeF4 square planar, XeF6 distorted octahedral, XeOF4 square pyramidal, XeO3 pyramidal.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept:
The shapes of xenon compounds come from VSEPR theory using bond pairs plus lone pairs around Xe.

Step 2: Match (a) XeF4:
Xe has 4 bond pairs and 2 lone pairs (octahedral electron geometry). The lone pairs sit opposite each other, so the shape is square planar: (a) - (ii).

Step 3: Match (b) XeF6:
Xe has 6 bond pairs and 1 lone pair. The lone pair distorts the octahedron, so the shape is distorted octahedral: (b) - (iii).

Step 4: Match (c) XeOF4:
Xe has 5 bond regions (4 Xe-F and 1 Xe=O) and 1 lone pair. The shape is square pyramidal: (c) - (iv).

Step 5: Match (d) XeO3:
Xe has 3 bond regions and 1 lone pair, so the shape is trigonal pyramidal: (d) - (i).

Step 6: Conclusion:
The set (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i) is option D. Options A, B and C each mismatch at least one pair.

Final Answer:
The correct matching is (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i). \[ \boxed{\text{(D) }\text{(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)}} \]