Question

Match List-I with List-II: 

List-I		List-II
(A)	DNA Helicase	(III)	Unwinds DNA Helix
(B)	DNA Polymerase I	(IV)	Removes RNA Primers
(C)	DNA Polymerase III	(II)	DNA Chain Elongation
(D)	DNA Ligase	(I)	Seals Nicks in DNA

• A. \(A\text{-IV},\ B\text{-II},\ C\text{-I},\ D\text{-III}\)
• B. \(A\text{-III},\ B\text{-IV},\ C\text{-II},\ D\text{-I}\)
• C. \(A\text{-III},\ B\text{-I},\ C\text{-II},\ D\text{-IV}\)
• D. \(A\text{-II},\ B\text{-III},\ C\text{-IV},\ D\text{-I}\)

Hint:

Remember:
• Helicase \(\rightarrow\) Unwinds DNA
• DNA Pol I \(\rightarrow\) Removes RNA primers
• DNA Pol III \(\rightarrow\) Main replication enzyme
• DNA ligase \(\rightarrow\) Seals Okazaki fragments

Answer 1

The Correct Option is B

Concept: DNA replication requires several enzymes working together to ensure accurate duplication of genetic material. Important enzymes include:
• DNA helicase
• DNA polymerases
• DNA ligase

Step 1: Matching DNA helicase. DNA helicase functions to: \[ \text{Unwind the DNA double helix} \] by breaking hydrogen bonds between complementary strands. Thus: \[ A \rightarrow III \]

Step 2: Matching DNA Polymerase I. DNA Polymerase I primarily functions in: \[ \text{Removal of RNA primers} \] through its \(5' \rightarrow 3'\) exonuclease activity. Thus: \[ B \rightarrow IV \]

Step 3: Matching DNA Polymerase III. DNA Polymerase III is the major enzyme responsible for: \[ \text{DNA chain elongation} \] during replication. Thus: \[ C \rightarrow II \]

Step 4: Matching DNA ligase. DNA ligase: \[ \text{Seals nicks in DNA} \] by forming phosphodiester bonds between adjacent DNA fragments. Thus: \[ D \rightarrow I \]

Step 5: Determining the correct combination. Therefore: \[ \boxed{ A\text{-III},\ B\text{-IV},\ C\text{-II},\ D\text{-I} } \] Hence, the correct answer is: \[ \boxed{(B)\ A\text{-III},\ B\text{-IV},\ C\text{-II},\ D\text{-I}} \]