Question

Match List-I with List-II.\[\begin{array}{|c|c|}\hline \textbf{J K Flip Flop Inputs} & \textbf{Next State} \\ \hline (A)\ 0\ 0 & (I)\ \text{No Change} \\ \hline (B)\ 0\ 1 & (II)\ \text{Reset} \\ \hline (C)\ 1\ 0 & (III)\ \text{Set} \\ \hline (D)\ 1\ 1 & (IV)\ \text{Toggle} \\ \hline \end{array}\]

• 1. (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• 2. (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
• 3. (A) - (I), (B) - (III), (C) - (IV), (D) - (II)
• 4. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Hint:

In JK flip-flops, different combinations of the inputs \(J\) and \(K\) determine the output, including toggle, set, reset, or no change.

Answer 1

The Correct Option is A

The JK flip-flop operates as follows: 

- **(A)** 0 0: The state toggles (flips between 0 and 1). 

- **(B)** 0 1: The state is set to 1. - **(C)** 1 0: The state is reset to 0. 

- **(D)** 1 1: The state remains unchanged. 

Thus, the correct mapping is: - (A) 0 0 → **(I)** Toggle - (B) 0 1 → **(II)** Set - (C) 1 0 → **(III)** Reset - (D) 1 1 → **(IV)** No Change