Question:

Match List - I (Fundamental Experiment) with List - II (its conclusion) and select the correct option from the choices given below the list:
List - IList - II
A. Franck-Hertz(i) Particle nature of light
B. Photo-electric(ii) Discrete energy levels of atom
C. Davison-Germer experiment(iii) Wave nature of electron
(iv) Structure of atom

Show Hint

Franck-Hertz showed quantised atomic energy levels, the photoelectric effect showed the particle (photon) nature of light, and Davisson-Germer showed electron diffraction.
Updated On: Nov 11, 2026
  • A \(-\) ii; B \(-\) i, C \(-\) iii
  • A \(-\) iv; B \(-\) iii, C \(-\) ii
  • A \(-\) i; B \(-\) iv, C \(-\) iii
  • A \(-\) ii; B \(-\) iv, C \(-\) iii
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

A. Franck-Hertz experiment: electrons lose energy only in discrete amounts when colliding with atoms, showing discrete energy levels of atom, so A - (ii).
B. Photo-electric effect: explained by photons (quanta of light), showing the particle nature of light, so B - (i).
C. Davisson-Germer experiment: electron diffraction from a nickel crystal, showing the wave nature of electron, so C - (iii).
Hence A-ii; B-i, C-iii.
Answer: (1) A \(-\) ii; B \(-\) i, C \(-\) iii
Was this answer helpful?
0
0

Top JEE Main Physics Questions

View More Questions