Step 1: Understanding the Question:
This question asks for the sum of two unknown eigenvalues of a \( 3 \times 3 \) matrix, given its characteristic polynomial and one of its eigenvalues.
Step 2: Key Formula or Approach:
Let \( \lambda_1, \lambda_2, \lambda_3 \) be the three eigenvalues of matrix \( A \).
The characteristic equation of a \( 3 \times 3 \) matrix \( A \) is represented as:
\[ x^3 - \text{tr}(A) \cdot x^2 + M \cdot x - |A| = 0 \]
where:
\( \text{tr}(A) \) is the trace of the matrix (sum of the diagonal elements).
\( |A| \) is the determinant of the matrix.
A key theorem in linear algebra states that the sum of the eigenvalues is equal to the trace of the matrix:
\[ \sum_{i=1}^3 \lambda_i = \lambda_1 + \lambda_2 + \lambda_3 = \text{tr}(A) \]
Step 3: Detailed Explanation:
• Identify the Trace from the Polynomial:
- The given characteristic polynomial is:
\[ f(x) = x^3 - 4x^2 - 11x + 30 \]
- Comparing this to the standard form \( x^3 - \text{tr}(A) \cdot x^2 + M \cdot x - |A| \), we find:
\[ \text{tr}(A) = 4 \]
- Therefore, the sum of all three eigenvalues must be:
\[ \lambda_1 + \lambda_2 + \lambda_3 = 4 \]
• Calculate the Sum of the Other Two Eigenvalues:
- We are given that one of the eigenvalues is \( -3 \). Let \( \lambda_1 = -3 \).
- Substitute this into the sum equation:
\[ -3 + \lambda_2 + \lambda_3 = 4 \]
\[ \lambda_2 + \lambda_3 = 4 + 3 = 7 \]
- Thus, the sum of the other two eigenvalues is exactly 7.
Step 4: Final Answer:
The sum of the other two eigenvalues is 7.
Therefore, the correct choice is option (D).