Question

Indicate the correct order of Taal according to increasing order of Matras: \[ \text{A. Trayashra Jati Dhruvtaal} \] \[ \text{B. Mishra Jati Dhruvtaal} \] \[ \text{C. Samkirna Jati Dhruvtaal} \] \[ \text{D. Khanda Jati Dhruvtaal} \] \[ \text{E. Chaturashra Jaati Dhruvtaal} \]

• A. A, E, B, C, D
• B. A, D, C, B, E
• C. A, E, D, B, C
• D. A, B, C, D, E

Hint:

Jati order shortcut: \[ \text{Tisra} \rightarrow \text{Chaturasra} \rightarrow \text{Khanda} \rightarrow \text{Mishra} \rightarrow \text{Samkirna} \]

Answer 1

The Correct Option is C

Concept:
In Carnatic tala system, jati changes the number of counts in Laghu. The jatis are arranged according to increasing matras as: \[ \text{Tisra} < \text{Chaturasra} < \text{Khanda} < \text{Mishra} < \text{Samkirna} \]

Step 1: Identify the smallest jati.
Trayashra or Tisra jati is the smallest among the given jatis. So: \[ A = \text{Trayashra Jati Dhruvtaal} \]

Step 2: Next jati is Chaturashra.
Chaturashra jati comes next. So: \[ E = \text{Chaturashra Jaati Dhruvtaal} \]

Step 3: Next comes Khanda.
Khanda jati comes after Chaturashra. So: \[ D = \text{Khanda Jati Dhruvtaal} \]

Step 4: Next comes Mishra.
Mishra jati has more counts than Khanda. So: \[ B = \text{Mishra Jati Dhruvtaal} \]

Step 5: Largest is Samkirna.
Samkirna jati has the highest number of counts among these. So: \[ C = \text{Samkirna Jati Dhruvtaal} \]

Step 6: Final arrangement.
Thus, the correct order is: \[ A \rightarrow E \rightarrow D \rightarrow B \rightarrow C \] Hence: \[ \boxed{\text{(C) A, E, D, B, C}} \]