Concept:
Tritaal has:
\[
16 \text{ matras}
\]
Tigun means three times the speed, and Aad means one and a half times the speed.
To find the space occupied, we divide the total matras by the laya multiplication.
Step 1: Find the duration of Tigun of one avartan.
Tritaal has:
\[
16 \text{ matras}
\]
In Tigun:
\[
\frac{16}{3}
\]
Step 2: Find the duration of Aad of one avartan.
Aad means:
\[
\frac{3}{2}
\]
times speed.
So, the duration is:
\[
16 \div \frac{3}{2}
\]
\[
=16 \times \frac{2}{3}
\]
\[
=\frac{32}{3}
\]
Step 3: Add Tigun and Aad durations.
\[
\frac{16}{3}+\frac{32}{3}=\frac{48}{3}
\]
\[
=16
\]
Step 4: Match the taal of 16 matras.
The taal having 16 matras is:
\[
\text{Tritaal}
\]
Step 5: Final conclusion.
Therefore, Tigun and Aad of Tritaal's one avartan together fall in one complete cycle of:
\[
\boxed{\text{Tritaal}}
\]
Hence:
\[
\boxed{\text{(B)}}
\]
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