In Young's double-slit experiment, the 10th-order maximum is obtained at the point of observation in the interference pattern for \( \lambda = 7000 \, \text{Ã} \). If the source is replaced by another one of wavelength 5000 Å, then the order of maximum at the same point will be â
In Young's double-slit experiment, the 10th-order maximum is obtained at the point of observation in the interference pattern for \( \lambda = 7000 \, \text{Ã} \). If the source is replaced by another one of wavelength 5000 Å, then the order of maximum at the same point will be â
Show Hint
- 12th
- 14th
- 16th
- 18th
The Correct Option is B
Solution and Explanation
Step 1: Use the formula for the fringe pattern.
The fringe pattern for Youngâs double slit experiment is given by \( d \sin \theta = n \lambda \), where \( d \) is the distance between the slits, \( \lambda \) is the wavelength, and \( n \) is the order of the maximum.
Step 2: Calculate the new order of the maximum.
Since the wavelength decreases, the order of the maximum increases proportionally, leading to the 14th order maximum for \( \lambda = 5000 \, \text{Ã } \). Final Answer: \[ \boxed{14th} \]
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