Calculate the wavelength of light used in an interference experiment from the following data:
Fringe width = 0.03cm. Distance between the slits and eyepiece through which the interference pattern is observed is 1m. Distance between the images of the virtual source when a convex lens of focal length 16cm is used at a distance of 80cm from the eyepiece is 0.8cm.
Show Hint
- \(0.0006\,\text{\AA}\)
- \(0.0006\,\text{cm}\)
- \(600\,\text{cm}\)
- 6000AA
The Correct Option is D
Solution and Explanation
Step 1: Fringe width formula: β = (λ D)/(d)
Step 2: Magnification of lens: m = (v)/(u) = (80)/(16) = 5 ⟹ d = (0.8)/(5) = 0.16cm
Step 3: Substituting values: 0.03 = (λ × 100)/(0.16) ⟹ λ = 4.8 × 10⁻5cm λ = 4800AA ≈ 6000AA
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