Question:
A ray of light of intensity I is incident on a parallel glass slab at point A as shown in the diagram. It undergoes partial reflection and refraction. At each reflection, 25% of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio of Imax and Imin is:
A ray of light of intensity I is incident on a parallel glass slab at point A as shown in the diagram. It undergoes partial reflection and refraction. At each reflection, 25% of incident energy is reflected. The rays AB and A'B' undergo interference. The ratio of Imax and Imin is:
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For interference: Imax/Imin = (a₁+a₂)²/(a₁-a₂)².
Updated On: Mar 20, 2026
- \(49:1\)
- \(7:1\)
- \(4:1\)
- 8:1
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The Correct Option is B
Solution and Explanation
Step 1: Reflected intensity I₁ = 0.25I, transmitted intensity I₂ = 0.75I.
Step 2: Amplitudes are proportional to square roots of intensities: a₁ : a₂ = √(0.25) : √(0.75) = 1 : √(3)
Step 3: Interference ratio: fracImaxImin = ((a₁+a₂)²)/((a₂-a₁)²) = frac(1+√(3))²(√(3)-1)² = 7
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