Question:
In the electron emission process, \( _{Z}^{A}X \rightarrow _{Z+1}^{A}Y + e^{-} + \bar{\nu} \), the particle \( q \) emitted along with the electron is:
In the electron emission process, \( _{Z}^{A}X \rightarrow _{Z+1}^{A}Y + e^{-} + \bar{\nu} \), the particle \( q \) emitted along with the electron is:
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Beta decay involves the emission of an antineutrino to conserve energy and lepton number.
Updated On: Apr 7, 2026
- Neutron
- Neutrino
- Antineutrino
- Proton
- Positron
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The Correct Option is C
Solution and Explanation
In beta-minus (\( \beta^- \)) decay, a neutron in the nucleus transforms into a proton, emitting an electron and an antineutrino (\(\bar{\nu}\)).
The reaction follows: \[ n \rightarrow p + e^{-} + \bar{\nu} \] The antineutrino is emitted to ensure the conservation of energy, angular momentum, and lepton number.
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