Step 1: Understanding the Question:
The problem presents a bipolar junction transistor connected in a Common Emitter (CE) configuration. Given the simultaneous changes in the emitter current ($\Delta I_E$) and collector current ($\Delta I_C$), we need to find the corresponding change required in the base current ($\Delta I_B$).
Step 2: Key Formula or Approach:
According to Kirchhoff's Current Law applied to a transistor structure, the total current entering the device must balance the currents exiting it. This gives the fundamental relationship:
$$I_E = I_B + I_C$$
Differentiating or taking changes on both sides yields:
$$\Delta I_E = \Delta I_B + \Delta I_C$$
Step 3: Detailed Explanation:
We are given the following variations:
Change in emitter current, $\Delta I_E = 8.0 \text{ mA}$
Change in collector current, $\Delta I_C = 7.8 \text{ mA}$
Rearranging the current relation equation to isolate the base current change ($\Delta I_B$):
$$\Delta I_B = \Delta I_E - \Delta I_C$$
Substitute the given numerical parameters:
$$\Delta I_B = 8.0 \text{ mA} - 7.8 \text{ mA} = 0.2 \text{ mA}$$
The options are given in microamperes ($\mu\text{A}$). Since $1 \text{ mA} = 1000 \; \mu\text{A}$, let's convert the units:
$$\Delta I_B = 0.2 \times 1000 \; \mu\text{A} = 200 \; \mu\text{A}$$
Step 4: Final Answer:
The required change in the base current is $200 \; \mu\text{A}$, which corresponds to option (A).