Question

For a common emitter transistor configuration the ratio of \(\frac{I_C}{I_E} = 0.96\), then the current gain in this configuration is

• A. 6
• B. 12
• C. 24
• D. 48

Hint:

Relation: $\beta = \frac{\alpha}{1-\alpha}$

Answer 1

The Correct Option is C

Concept: \[ \alpha = \frac{I_C}{I_E}, \quad \beta = \frac{\alpha}{1-\alpha} \]

Step 1: Given $\alpha = 0.96$.

Step 2: Calculate $\beta$. \[ \beta = \frac{0.96}{1 - 0.96} = \frac{0.96}{0.04} = 24 \]

Step 3: Conclusion.
Current gain = 24 Final Answer: Option (C)