Question:

In a reversed-biased p-n junction diode, the applied voltage mostly drops across :

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In reverse bias, the depletion layer widens and behaves like a high-resistance region. Therefore, almost the entire reverse voltage appears across the depletion region.
  • p-region only
  • n-region only
  • depletion region
  • the diode
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The Correct Option is C

Solution and Explanation

Concept: A p-n junction consists of: \[ \text{p-region} \] and \[ \text{n-region}. \] At the junction, diffusion of charge carriers creates a depletion region containing immobile ions. This depletion region behaves as an insulating layer and possesses very high resistance compared to the p-region and n-region.

Step 1:
Understand reverse biasing. In reverse bias, \[ p\text{-side} \] is connected to the negative terminal and \[ n\text{-side} \] is connected to the positive terminal. The external voltage increases the width of the depletion layer.

Step 2:
Analyze the resistance of different regions. The p-region and n-region contain majority charge carriers and therefore possess relatively low resistance. The depletion region contains almost no free charge carriers and therefore has very high resistance.

Step 3:
Apply the voltage division principle. In any circuit, the larger voltage drop occurs across the region having the larger resistance. Since the depletion region offers maximum resistance, \[ \text{most of the applied reverse voltage} \] appears across the depletion region.

Step 4:
Write the final conclusion. Hence, in a reverse-biased p-n junction diode, the applied voltage mostly drops across the \[ \boxed{\text{depletion region}}. \] Therefore, \[ \boxed{\text{(C)}} \] is the correct answer.
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