Question:
In a purely inductive circuit, current
In a purely inductive circuit, current
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In an inductor, current lags voltage by \(90^\circ\). Remember: L in lag.
Updated On: May 27, 2026
- Leads voltage by \(90^\circ\)
- Lags voltage by \(90^\circ\)
- Is in phase with voltage
- Leads voltage by \(180^\circ\)
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The Correct Option is B
Solution and Explanation
Concept:
In a purely inductive AC circuit, voltage leads current by \(90^\circ\).
Step 1: For an inductor: \[ v=L\frac{di}{dt} \]
Step 2: This means voltage depends on the rate of change of current.
Step 3: Hence, voltage reaches its maximum before current.
Step 4: Therefore, current lags voltage by: \[ 90^\circ \] Hence: \[ \boxed{\text{Lags voltage by }90^\circ} \]
Step 1: For an inductor: \[ v=L\frac{di}{dt} \]
Step 2: This means voltage depends on the rate of change of current.
Step 3: Hence, voltage reaches its maximum before current.
Step 4: Therefore, current lags voltage by: \[ 90^\circ \] Hence: \[ \boxed{\text{Lags voltage by }90^\circ} \]
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