Question:
In a purely capacitive circuit, current
In a purely capacitive circuit, current
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In a capacitor, current leads voltage by \(90^\circ\). Remember: C in lead.
Updated On: May 27, 2026
- Lags voltage by \(90^\circ\)
- Leads voltage by \(90^\circ\)
- Is in phase with voltage
- Is zero
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The Correct Option is B
Solution and Explanation
Concept:
In a purely capacitive AC circuit, current leads voltage by \(90^\circ\).
Step 1: For a capacitor: \[ i=C\frac{dv}{dt} \]
Step 2: This means current depends on the rate of change of voltage.
Step 3: Hence, current reaches its maximum before voltage.
Step 4: Therefore, current leads voltage by: \[ 90^\circ \] Hence: \[ \boxed{\text{Leads voltage by }90^\circ} \]
Step 1: For a capacitor: \[ i=C\frac{dv}{dt} \]
Step 2: This means current depends on the rate of change of voltage.
Step 3: Hence, current reaches its maximum before voltage.
Step 4: Therefore, current leads voltage by: \[ 90^\circ \] Hence: \[ \boxed{\text{Leads voltage by }90^\circ} \]
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