Question:
In a photoelectric experiment, frequency \(f = 1\).\(5f_0\) (\(f_o\): threshold frequency). If the frequency of light is changed to \(\frac{f}{2}\), then photocurrent becomes (intensity of light has doubled)
In a photoelectric experiment, frequency \(f = 1\).\(5f_0\) (\(f_o\): threshold frequency). If the frequency of light is changed to \(\frac{f}{2}\), then photocurrent becomes (intensity of light has doubled)
Updated On: Jan 13, 2026
- Zero
- Doubled
- Same
- Thrice
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The Correct Option is A
Solution and Explanation
The Correct Option is (A) : Zero
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Concepts Used:
Photoelectric Effect
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
Photoelectric Effect Formula:
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,
- h is Planck’s constant.
- ν is the frequency of the incident photon.
- W is a work function.
- E is the maximum kinetic energy of ejected electrons: 1/2 mv².
Laws of Photoelectric Effect:
- The photoelectric current is in direct proportion to the intensity of light, for a light of any given frequency; (γ > γ Th).
- There exists a certain minimum (energy) frequency for a given material, called threshold frequency, below which the discharge of photoelectrons stops completely, irrespective of how high the intensity of incident light is.
- The maximum kinetic energy of the photoelectrons increases with the increase in the frequency (provided frequency γ > γ Th exceeds the threshold limit) of the incident light. The maximum kinetic energy is free from the intensity of light.
- The process of photo-emission is an instantaneous process.