Question:
In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased :
In a photoelectric effect experiment, the graph of stopping potential V versus reciprocal of wavelength obtained is shown in the figure. As the intensity of incident radiation is increased :
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The stopping potential depends on the frequency (wavelength) and the work function only, not on the intensity.
Updated On: Nov 5, 2026
- Slope of the straight line get more steep
- Graph does not change
- Straight line shifts to left
- Straight line shifts to right
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The Correct Option is B
Solution and Explanation
Einstein's equation: \(eV_0 = \dfrac{hc}{\lambda} - \phi\), i.e. \(V_0 = \dfrac{hc}{e}\cdot\dfrac{1}{\lambda} - \dfrac{\phi}{e}\).
The graph of V0 against \(1/\lambda\) is a straight line with slope \(hc/e\) (a universal constant) and intercept \(-\phi/e\) (fixed by the metal).
Increasing the intensity only increases the number of photons per second, hence the photocurrent; it does not change the maximum kinetic energy of the electrons or the stopping potential.
So the graph does not change.
Answer: (2) Graph does not change
The graph of V0 against \(1/\lambda\) is a straight line with slope \(hc/e\) (a universal constant) and intercept \(-\phi/e\) (fixed by the metal).
Increasing the intensity only increases the number of photons per second, hence the photocurrent; it does not change the maximum kinetic energy of the electrons or the stopping potential.
So the graph does not change.
Answer: (2) Graph does not change
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