Question

In a part of a circuit shown: Find V_A – V_B in volts. It is given that current is decreasing at a rate of 1 ampere/s.

Answer 1

Correct Answer: 18

The voltage equation across the circuit is given by: 

\[ V_A - iR - L \frac{di}{dt} - 12 = V_B \]

Rewriting, we get:

\[ V_A - V_B = iR + L \frac{di}{dt} + 12 \]

Given that the potential difference between points A and B is:

\[ V_A - V_B = +18 \, \text{volts} \]

Final Answer:

\(V_A - V_B = +18 \, \text{volts}\)