The convolution of \( x[n] \) with itself, \( y[n] = x[n] \ast x[n] \), is given by:
\[
y[n] = \sum_{k} x[k] \cdot x[n-k]
\]
Computing the convolution manually:
\[
y[0] = 1, \quad y[1] = 0, \quad y[2] = -2, \quad y[3] = 3
\]
Thus, the maximum value of \( y[n] \) is 9. Therefore, the correct answer is option (2).
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