Question:
If we choose velocity \(V\), length \(L\) and force \(F\) as fundamental physical quantities, then how would you express power in terms of \(V\), \(L\) and \(F\)?
If we choose velocity \(V\), length \(L\) and force \(F\) as fundamental physical quantities, then how would you express power in terms of \(V\), \(L\) and \(F\)?
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Power \(P=\frac{\text{Work}}{\text{time}}=\frac{F\times s}{t}=Fv\). So power is force multiplied by velocity.
Updated On: May 7, 2026
- \(F^1L^0V^1\)
- \(F^1L^{-1}V^1\)
- \(F^1L^{-1}V^2\)
- \(F^1L^{-2}V^{-3}\)
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The Correct Option is A
Solution and Explanation
Power is defined as the rate of doing work:
\[
P=\frac{W}{t}.
\]
Work is given by:
\[
W=F\times s.
\]
So power becomes:
\[
P=\frac{F\times s}{t}.
\]
But
\[
\frac{s}{t}=\text{velocity}=V.
\]
Therefore,
\[
P=F\times V.
\]
Now express this in terms of \(F\), \(L\), and \(V\).
Since power contains force \(F\) once:
\[
F^1.
\]
It contains velocity \(V\) once:
\[
V^1.
\]
It does not contain length \(L\) separately:
\[
L^0.
\]
Therefore,
\[
P=F^1L^0V^1.
\]
Hence, power in terms of \(F\), \(L\), and \(V\) is:
\[
F^1L^0V^1.
\]
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