Step 1: Understanding the Question:
We are given the magnitudes of two vectors, $|\vec{a}| = 4$ and $|\vec{b}| = 5$. We need to find the scalar values of $k$ that make the linear combination vectors $(\vec{a} + k\vec{b})$ and $(\vec{a} - k\vec{b})$ perpendicular to each other.
Step 2: Key Formula or Approach:
Two non-zero vectors are perpendicular if and only if their vector dot product is exactly zero:
$$(\vec{a} + k\vec{b}) \cdot (\vec{a} - k\vec{b}) = 0$$
We will use the distributive properties of the dot product along with the identity $\vec{v} \cdot \vec{v} = |\vec{v}|^2$.
Step 3: Detailed Explanation:
Expand the dot product expression using algebraic distribution:
$$\vec{a} \cdot \vec{a} - k(\vec{a} \cdot \vec{b}) + k(\vec{b} \cdot \vec{a}) - k^2(\vec{b} \cdot \vec{b}) = 0$$
Since the dot product is commutative ($\vec{a} \cdot \vec{b} = \vec{b} \cdot \vec{a}$), the middle cross-terms cancel each other out completely:
$$|\vec{a}|^2 - k^2|\vec{b}|^2 = 0$$
Substitute the given numerical magnitudes ($|\vec{a}| = 4$ and $|\vec{b}| = 5$) into this equation:
$$(4)^2 - k^2(5)^2 = 0$$
$$16 - 25k^2 = 0 \implies 25k^2 = 16$$
Isolate the squared scalar variable:
$$k^2 = \frac{16}{25}$$
Taking the square root of both sides gives the final values for $k$:
$$k = \pm \frac{4}{5}$$
This matches the choice provided in option (D).
Step 4: Final Answer:
The values of $k$ are $\pm \frac{4}{5}$, which corresponds to option (D).